A Llittle Bit More As To Conformal Dimension

A physical dimensionality, for all intensive purposes, is discrete -- when one considers the number of spatial dimensions plus time. Yet, if you want to get technical, since superstrings bear discrepencies that I term of as partitions, the conformal dimension of a superstring is never precisely One or Two, respectively. The conformal dimension of a one-dimensional superstring will vary -- depending upon the discrete truncation as to the scalar amplitude of the given arbitrary degree of Lorentz-Four-Contraction that would here correspond. If a one-dimensional superstring is "contracted" by a factor of two to just under three, then, it will have 15*10^7 mentioned partitional discrepencies along its topological contour. Yet, if a one-dimensional superstring is "contracted" by a factor of 3*10^8, then, it will have only one mentioned partitional discrepencies along its topological contour. The conformal dimension of a superstring with two of such partitions will be 2^((15*10^7)/10^43)). A similar situation is true for two-dimensional superstrings, except, a bosonic superstring also has one of such partitons, if it is going at the speed of light. (Only bosonic strings can travel at exactly the speed of light.) Also, if a superstring has two of such partitions, its conformal dimension will be 1+2^((15*10^7)/10^43). As an ansantz, 2^((15*10^7)/10^43) is basically one, since any number to the zero power is one. Although, a swivel-like-shaped superstring is more likely to become unoriented at the Bette Action, and, therefore, it is more likely to become tachyonic than if it were shaped otherwise. To Be Continued.