Course 3 on Lorentz-Four-Contractions, Last Test Solutions, Part 1

1) At .5c, the superstrings of the given object closest region along the given axis would contract lengthwise according to l = ((1-v^2/c^2)^.5). The superstrings of the given object that surrounded the prior mentioned region would contract moderately. The superstrings that did not define the length of the given object, and thus were furthest from the center of the specific axis given, would not contract at all, since the superstrings here would not define the length of the given object.

2) Matter and kinetic energy that are of a Kaluza-Klein light-cone-gauge topology contract relative to light because, since light is the result of the recycling of differential geometries, and all motion that involves mass that is of an abelian light-cone-gauge topology moves relative to the basis of such recycling, the physical parameters associated with such phenomena of mass must alter when such phenomena change in kinematic differentiation relative to light.

3) l = ((1-v^2/c^2)^.5, m = (1/(1-v^2/c^2)^.5), and relative to one traveling just under light speed, t = (1-v^2/c^2)^.5, or the proportion of more time noticed by a stander by as compared to one traveling just under light speed would obey t = (1/(1-v^2/c^2)^.5).

4) Its length would contract by .6, its mass would increase by (1/.6), and, the amount of time noticed by the one going at .8c would be .6 of the time of a stander by.

5) A mass with a Kaluza-Klein light-cone-gauge topology can not travel at light speed or else it would have all of the mass in space and time. This is because a Kaluza-Klein light-cone-gauge topology is abelian, and such topology bears a maximum fractal modulae in terms of its Gliossi field generation as encountered with just under light speed, and you can not increase such a fractal stress and expect it to obey the properties of a non-abelian light-cone-gauge topology.

6) Since the center of such strings specifically travels at .8c, this central region would contract according to (1-v^2/c^2)^.5 and (1/(1-v^2/c^2)^.5), and, the Lorentz-Four-Contractions would ease homeomorphically as one examines the further regions of the kinematic strings involved here.

7) The strings that are directly in the path of the directoralizations that moves at the given "quick" speed would contract in their given directoralizations according to Einstein's equations. Yet, since the two phenomena moving at the "quick" speed are differentiating in a multiplicit directoralization, the observation of such contractions would form a radial covariance that would be non-trivially isomorphic. The superstrings that are slower would also obey Einstein's equations would contract less.

8) A spherical object consisting of many superstrings that is moving in a unitary direction and is not spinning, orbiting, nor otherwise radially differentiating kinematically will only contract lengthwise toward the center of its directoralization, and would thus not contract uniformally.

Course 3 on Lorentz-Four-Contractions, Last Test, Part 1

1) if an object is traveling along a specific axis in general at .5c, describe what strings will be contracted according to the equation I gave, which strings would not be contracted at all lengthwise as a unit, and which strings would contract moderately in the globally distinguishable.

2) Why does matter and kinetic energy contract relative to light?

3) What are the basic equations for Lorentz-Four-Contractions?

4) If an object were to travel at .8c, how would its length, width, mass, and time be effected by a stander by?

5) Why can't a mass travel at light speed if it has a Kaluza-Klein light-cone-gauge topology?

6) A perfect "X" of two strings travels in the direction of the gap between them at .8c, describe the contraction of both lines that comprise the "X." (The strings would never collide.)

7) If an object is traveling in a different direction than that direction that is changing at close to light speed, yet certain of its strings are moving at the quicker string's speed, how will that object contract quantitatively?

8) Will any spherical object Lorentz-Contract uniformally if it is traveling in one direction at less than light speed? Why?

Lorentz-Four-Contractions, Session 7, Part 1

How does motion change as it exists relative to light? First, let us look at how time varies for an object relatively speaking as the given object changes in speed. This is because time is the "procedure" in which events take place, and the occurrence of events requires some sort of material medium which we signify here an "object." If you had 300 runners, and they ran a race, yet they all finished the race at different times, then, if they all started the race at the same "place" and at the same "time", then all 300 runners would have averaged a different speed during the race. Since having a different average speed means that one has had a different motion in terms of speed relative to light, that would mean that the extrapolated time that all 300 runners encountered during the race would be different. Yet how fast is light. Very much faster than any of the runners. So much faster that any differences in the extrapolated time that any of the runners would encounter would be quite minimal. Now let's say you were in a rocket ship that traveled eight-tenths of the speed of light. Let us say that you traveled in this ship for what would be for you six seconds. The amount of time elapsed on earth would be roughly 10 seconds. How do I figure? The rocket, including yourself, is traveling at eight-tenths the speed of light, or .8c. .8 squared is .64. 1-.64 = .36. the square root of .36 is .6. This means that .6 seconds for you in the ship would happen for you in the ship, while one second would happen here on earth for a standerby who was motionless. Or, 6 seconds would happen for you in the ship while 10 seconds would happen down on earth. The equation for this is:
t=(1-(v^2/c^2)^.5).