Monday, March 1, 2010

Lorentz-Four-Contractions, Session 7, Part 1

How does motion change as it exists relative to light? First, let us look at how time varies for an object relatively speaking as the given object changes in speed. This is because time is the "procedure" in which events take place, and the occurrence of events requires some sort of material medium which we signify here an "object." If you had 300 runners, and they ran a race, yet they all finished the race at different times, then, if they all started the race at the same "place" and at the same "time", then all 300 runners would have averaged a different speed during the race. Since having a different average speed means that one has had a different motion in terms of speed relative to light, that would mean that the extrapolated time that all 300 runners encountered during the race would be different. Yet how fast is light. Very much faster than any of the runners. So much faster that any differences in the extrapolated time that any of the runners would encounter would be quite minimal. Now let's say you were in a rocket ship that traveled eight-tenths of the speed of light. Let us say that you traveled in this ship for what would be for you six seconds. The amount of time elapsed on earth would be roughly 10 seconds. How do I figure? The rocket, including yourself, is traveling at eight-tenths the speed of light, or .8c. .8 squared is .64. 1-.64 = .36. the square root of .36 is .6. This means that .6 seconds for you in the ship would happen for you in the ship, while one second would happen here on earth for a standerby who was motionless. Or, 6 seconds would happen for you in the ship while 10 seconds would happen down on earth. The equation for this is:
t=(1-(v^2/c^2)^.5).

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