Next As To Binary And Tertiary Lagrangian-Based Paths

If a given arbitrary tense of a cohomological stratum, that is here to be formed by the respective action of the Fourier Transformation, that is of a correlative given arbitrary bosonic orbifold eigenset, is to here to be of either a binary Lagrangian-based path or of a tertiary Lagrangian-based path -- then, such a tense of a cohomological stratum, is a bit more likely to work to then be of a Duboult (Dubeault) nature of cohomology -- than such a symplectic residue of motion would otherwise be, if that respective activity of the Fourier Transformation of the said correlative given arbitrary bosonic orbifold eigenset were to, instead, to be of a unitary Lagrangian-based path.  Consequently -- if a given arbitrary tense of a cohomological stratum, that is here to be formed by the respective action of the Fourier Transformation of a correlative given arbitrary bosonic orbifold eigenset, is to here to be of a unitary Lagrangian-based path -- then,  such a tense of a cohomological stratum is a bit more likely to work to be of a De Rham nature of cohomology -- than such a symplectic residue of motion would otherwise be, if that respective activity of the Fourier Transformation of the said correlative given arbitrary bosonic orbifold eigenset were to, instead, to be of either of a binary or of a tertiary Lagrangian-based path.
I will continue with the suspense later!  To Be Continued!  Sincerely, Samuel David Roach.