Wednesday, August 28, 2019

Majorana-Weyl-Invariant-Spinor And Tense Of Cohomology

When a Majorana-Weyl-Invariant-Spinor is to be transferred in a linear manner that is not perturbative, it tends to work to form a De Rham cohomology; whereas -- when a Majorana-Weyl-Invariant-Spinor is to be transferred in either a parabolic manner or in an elliptical manner that is not perturbative, it tends to work to form a Dolbeault cohomology.  To Be Continued!  Sincerely, Sam.

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